Optimal. Leaf size=94 \[ -\frac{a^4}{7 b^5 \left (a+b x^2\right )^{7/2}}+\frac{4 a^3}{5 b^5 \left (a+b x^2\right )^{5/2}}-\frac{2 a^2}{b^5 \left (a+b x^2\right )^{3/2}}+\frac{4 a}{b^5 \sqrt{a+b x^2}}+\frac{\sqrt{a+b x^2}}{b^5} \]
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Rubi [A] time = 0.0531119, antiderivative size = 94, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.133, Rules used = {266, 43} \[ -\frac{a^4}{7 b^5 \left (a+b x^2\right )^{7/2}}+\frac{4 a^3}{5 b^5 \left (a+b x^2\right )^{5/2}}-\frac{2 a^2}{b^5 \left (a+b x^2\right )^{3/2}}+\frac{4 a}{b^5 \sqrt{a+b x^2}}+\frac{\sqrt{a+b x^2}}{b^5} \]
Antiderivative was successfully verified.
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Rule 266
Rule 43
Rubi steps
\begin{align*} \int \frac{x^9}{\left (a+b x^2\right )^{9/2}} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{x^4}{(a+b x)^{9/2}} \, dx,x,x^2\right )\\ &=\frac{1}{2} \operatorname{Subst}\left (\int \left (\frac{a^4}{b^4 (a+b x)^{9/2}}-\frac{4 a^3}{b^4 (a+b x)^{7/2}}+\frac{6 a^2}{b^4 (a+b x)^{5/2}}-\frac{4 a}{b^4 (a+b x)^{3/2}}+\frac{1}{b^4 \sqrt{a+b x}}\right ) \, dx,x,x^2\right )\\ &=-\frac{a^4}{7 b^5 \left (a+b x^2\right )^{7/2}}+\frac{4 a^3}{5 b^5 \left (a+b x^2\right )^{5/2}}-\frac{2 a^2}{b^5 \left (a+b x^2\right )^{3/2}}+\frac{4 a}{b^5 \sqrt{a+b x^2}}+\frac{\sqrt{a+b x^2}}{b^5}\\ \end{align*}
Mathematica [A] time = 0.0281393, size = 61, normalized size = 0.65 \[ \frac{560 a^2 b^2 x^4+448 a^3 b x^2+128 a^4+280 a b^3 x^6+35 b^4 x^8}{35 b^5 \left (a+b x^2\right )^{7/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.004, size = 58, normalized size = 0.6 \begin{align*}{\frac{35\,{x}^{8}{b}^{4}+280\,a{x}^{6}{b}^{3}+560\,{a}^{2}{x}^{4}{b}^{2}+448\,{a}^{3}{x}^{2}b+128\,{a}^{4}}{35\,{b}^{5}} \left ( b{x}^{2}+a \right ) ^{-{\frac{7}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.34429, size = 217, normalized size = 2.31 \begin{align*} \frac{{\left (35 \, b^{4} x^{8} + 280 \, a b^{3} x^{6} + 560 \, a^{2} b^{2} x^{4} + 448 \, a^{3} b x^{2} + 128 \, a^{4}\right )} \sqrt{b x^{2} + a}}{35 \,{\left (b^{9} x^{8} + 4 \, a b^{8} x^{6} + 6 \, a^{2} b^{7} x^{4} + 4 \, a^{3} b^{6} x^{2} + a^{4} b^{5}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 5.56295, size = 454, normalized size = 4.83 \begin{align*} \begin{cases} \frac{128 a^{4}}{35 a^{3} b^{5} \sqrt{a + b x^{2}} + 105 a^{2} b^{6} x^{2} \sqrt{a + b x^{2}} + 105 a b^{7} x^{4} \sqrt{a + b x^{2}} + 35 b^{8} x^{6} \sqrt{a + b x^{2}}} + \frac{448 a^{3} b x^{2}}{35 a^{3} b^{5} \sqrt{a + b x^{2}} + 105 a^{2} b^{6} x^{2} \sqrt{a + b x^{2}} + 105 a b^{7} x^{4} \sqrt{a + b x^{2}} + 35 b^{8} x^{6} \sqrt{a + b x^{2}}} + \frac{560 a^{2} b^{2} x^{4}}{35 a^{3} b^{5} \sqrt{a + b x^{2}} + 105 a^{2} b^{6} x^{2} \sqrt{a + b x^{2}} + 105 a b^{7} x^{4} \sqrt{a + b x^{2}} + 35 b^{8} x^{6} \sqrt{a + b x^{2}}} + \frac{280 a b^{3} x^{6}}{35 a^{3} b^{5} \sqrt{a + b x^{2}} + 105 a^{2} b^{6} x^{2} \sqrt{a + b x^{2}} + 105 a b^{7} x^{4} \sqrt{a + b x^{2}} + 35 b^{8} x^{6} \sqrt{a + b x^{2}}} + \frac{35 b^{4} x^{8}}{35 a^{3} b^{5} \sqrt{a + b x^{2}} + 105 a^{2} b^{6} x^{2} \sqrt{a + b x^{2}} + 105 a b^{7} x^{4} \sqrt{a + b x^{2}} + 35 b^{8} x^{6} \sqrt{a + b x^{2}}} & \text{for}\: b \neq 0 \\\frac{x^{10}}{10 a^{\frac{9}{2}}} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.72733, size = 96, normalized size = 1.02 \begin{align*} \frac{35 \, \sqrt{b x^{2} + a} + \frac{140 \,{\left (b x^{2} + a\right )}^{3} a - 70 \,{\left (b x^{2} + a\right )}^{2} a^{2} + 28 \,{\left (b x^{2} + a\right )} a^{3} - 5 \, a^{4}}{{\left (b x^{2} + a\right )}^{\frac{7}{2}}}}{35 \, b^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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